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An exponential function f(x) = ab^x passes through the points (0,3) and (2,27) what are the values of a and b?

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Answer: f(x) = 3(3)^x, where a = 3 and b = 3

Step 1: We can use the two given points to form a system of two equations and solve for the variables a and b.

  • From the first point (0,3), we know that:

f(0) = ab^0 = a = 3

  • From the second point (2,27), we know that:

f(2) = ab^2 = 27

Step 2: We can divide both sides of the second equation by the first equation to eliminate a and obtain:

(ab^2)/(ab^0) = 27/3

b^2 = 9

Taking the square root of both sides, we get:

b = ±3

b = 3

We need to use the positive 3 for b

Step 3: We can now substitute the value of b into one of the equations to solve for a. Let's use the first equation:

3 = a(3)^0

3 = a(1)

3 = a

Therefore, the values of a and b are a = 3 and b = 3.

So, the exponential function that passes through the points (0,3) and (2,27) is f(x) = 3(3)^x, while the value of a = 3 and the value of b = 3 also.

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