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a typical sond level for a buzzing mosquito is 40 db, and a normal conversation is approximately 50 db. how manybuzing mosquitos

1 Answer

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To determine how many buzzing mosquitoes it would take to reach a sound level of a normal conversation, we can use the fact that sound intensity (in decibels) is logarithmic and can be expressed as:

dB = 10 log(I/I₀)

where I is the sound intensity of the source, I₀ is a reference sound intensity (usually taken to be the threshold of human hearing, which is 1 x 10^-12 W/m^2), and dB is the sound level in decibels.

If we rearrange this equation to solve for I, we get:

I = I₀ 10^(dB/10)

Now, we can use this equation to calculate the sound intensity of one buzzing mosquito, given that its sound level is 40 dB:

I₁ = I₀ 10^(40/10) = I₀ 10^4

Similarly, we can calculate the sound intensity of a normal conversation, given that its sound level is 50 dB:

I₂ = I₀ 10^(50/10) = I₀ 10^5

To find how many mosquitoes it would take to produce the same sound intensity as a normal conversation, we can divide I₂ by I₁:

n = I₂ / I₁ = (I₀ 10^5) / (I₀ 10^4) = 10

So, it would take approximately 10 buzzing mosquitoes to produce the same sound intensity as a normal conversation.

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User Graham Smith
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