Question

The 68 students who responded to the awesome survey selected the first letter of their name along with something they like to do in their spare time. The results are shown in the table below.

What is the probability that a randomly selected student has a name that starts with A-E or likes to cook?
Round your answer to the nearest hundreth. Thank you! :)

Answer 1

0.49

Explanation:

You want the probability that a random student has a name starting with A–E or likes to cook.

Probability

The required probability is ...

P(A–E ∪ cooks) = P(A–E) +P(cooks) -P(A–E ∩ cooks)

P(A–E ∪ cooks) = (30/68) +(8/68) -(5/68)

P(A–E ∪ cooks) = (30 +8 -5)/68 = 33/68 ≈ 0.49

The probability of interest is about 0.49.

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Additional comment

The numbers in each category are found in the totals column and row, and in the cell at the intersection of the row and column. The probability is the relevant number, divided by the total number of students, which is 68.

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