Question

800 J of heat were added to 130.0 gram piece of iron (Cp = 0.45 J/g°C), initially at 55.0°C. Determine teh final temperature in °C.​

Answer 1

Step-by-step explanation:

The equation that relates heat, mass, specific heat, and temperature change is:

Q = mCpΔT

where Q is the heat added, m is the mass of the substance, Cp is the specific heat capacity of the substance, and ΔT is the change in temperature.

Rearranging the equation to solve for ΔT, we get:

ΔT = Q / (mCp)

Substituting the given values, we get:

ΔT = 800 J / (130.0 g × 0.45 J/g°C)

ΔT = 12.97°C

This is the change in temperature. To find the final temperature, we add this to the initial temperature:

Final temperature = 55.0°C + 12.97°C = 67.97°C

Therefore, the final temperature of the iron piece is 67.97°C.