Question

A rocket was launched from Cape Canaveral with a mass of 733,000 kg with a starting

thrust (Force) of 5,560,500 N. What is the acceleration of the rocket right after the
F
common booster ignites? a =
772
O 4.28 m/s^2
O 4.07 x10^12 m/s^2
O 412 m/s^2
O 7.59 m/s^2

Answer 1

O 7.59 m/s^2

Step-by-step explanation:

We can use Newton's Second Law, which states that force (F) equals mass (m) multiplied by acceleration (a), or F = ma. Rearranging this equation, we can find the acceleration:

a = F/m

Substituting the given values, we get:

a = 5,560,500 N / 733,000 kg

a = 7.59 m/s^2

Therefore, the acceleration of the rocket right after the booster ignites is 7.59 m/s^2.