Question

If x7y5 is exactly divisible by 3, then the least value of (x + y) is

Answer 1

Explanation:

x7y5 is exactly divisible by 3

then ,

x + 7 + y + 5 is divisible by 3

x + y + 12 is divisible by 3

Least value of x + y = 3

It cannot be zero because x + y = 0 means x = 0 & y = 0

but x
`\\eq` 0 because it would be a 3 digit number not 4 digit .