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PLEASE DO THESE 2 THANK YOU!

Complete the square for each equation.
1.) 9y^2-x-18y+10=0

2.) 4y^2+x+8y+1=0

1 Answer

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1.) To complete the square for the equation 9x^2 - x - 18 + 10 = 0, we first need to isolate the x term on one side of the equation. Adding 8 to both sides, we get:

9x^2 - x - 8 = 0

Next, we divide both sides by 9 to get the coefficient of x^2 to be 1:

x^2 - (1/9)x - (8/9) = 0

Now, we can complete the square by adding and subtracting (1/18)^2 to the left side of the equation:

x^2 - (1/9)x + (1/18)^2 - (8/9) - (1/18)^2 = 0

Simplifying the left side, we get:

(x - 1/18)^2 - 145/324 = 0

2.) To complete the square for the equation 4y^2 + x + 8y + 1 = 0, we first need to isolate the y terms on one side of the equation. Subtracting 1 and rearranging the terms, we get:

4y^2 + 8y = -x - 1

Next, we can complete the square for the y terms by adding and subtracting (8/4)^2 to the left side of the equation:

4(y + 1)^2 - 16 = -x - 1

Simplifying the left side, we get:

4(y + 1)^2 = -x + 15

Finally, we can divide both sides by 4 to get the coefficient of the y^2 term to be 1:

(y + 1)^2 = (-1/4)x + 15/4
answered
User Byron Whitlock
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