We can use Hooke's Law to calculate the effective spring constant of the spring system.
Hooke's Law states that the force exerted by a spring is proportional to its extension or compression from its equilibrium position. The formula for Hooke's Law is:
F = -kx
where F is the force exerted by the spring, k is the spring constant, and x is the displacement of the spring from its equilibrium position.
In this problem, the driver has a weight of 60 kg. The force exerted by the spring is equal to the weight of the driver, so we can write:
F = mg = (60 kg)(9.8 m/s^2) = 588 N
The displacement of the spring is given as 2.4×10−2 m.
We can now use Hooke's Law to solve for the spring constant:
k = -F/x = -(588 N)/(2.4×10−2 m) = -24500 N/m
The effective spring constant of the spring system in the taptap is 24500 N/m.