Question

How many grams of NaCl are needed to make 0.200 L of a 7.5 M solution?

Answer 1

Step-by-step explanation:

.200 L * 7.5 moles / L = 1.5 moles of NaCl

Each mole of NaCl weighs 22.99 + 35.45 =58.44 gm/mole

58.44 gm/mole * 1.5 mole = 87.66 gm