Answer: Since h(x) has only one critical point, it must occur at x = 2. Therefore, we need to examine the behavior of h(x) to the left and right of x = 2 to determine the global maximum and minimum.
To the left of x = 2, h′(x) = -1, which means that h(x) is decreasing. Therefore, the global maximum must occur at x = 2.
To the right of x = 2, h′(x) = 1, which means that h(x) is increasing. Therefore, the global minimum must occur at x = 4.
Therefore, the exact answers are:
The global maximum occurs when x= 2.
The global minimum occurs when x= 4.