Question

Use the quadratic formula to solve the equation.

-4x²-15x+4=0
Select the correct choice below and, if necessary, fill in the answer box to complete your choice.
O A.
X=
(Use a comma to separate answers as needed.)
www.
OB. The solution is not a real number.

Answer 1

Option A. x = -4, or x = 1/4

Explanation:

The question directs us to use the quadratic formula to solve the equation.

The quadratic formula applies for a one-variable quadratic equation in the form
`ax^(2) +bx+c=0`, and gives solutions
`x=\frac{-b \pm \sqrt {b^2 -4ac}}{2a}`

Since the equation given in the question,
`-4x^(2) -15x+4=0`, is in the required form, with
`a=-4, ~~b=-15,~\text{and}~~c=4`, then the solutions are given by the formula:

`x=\frac{-b \pm \sqrt {b^2 -4ac}}{2a}`

`x=\frac{-(-15) \pm \sqrt {(-15)^2 -4(-4)(4)}}{2(-4)}`

`x=\frac{15 \pm \sqrt {225 +64}}{-8}`

`x=\frac{15 \pm \sqrt {289}}{-8}`

`x=(15 \pm 17)/(-8)`

`x=(15 + 17)/(-8),~~\text{ or }~~x=(15 - 17)/(-8)`

`x=(32)/(-8),~~\text{ or }~~x=(-2)/(-8)`

`x=-4,~~\text{ or }~~x=(1)/(4)`

Answer 2

the correct choice is A and the solutions are -4 and 0.25.

Explanation: