Question

Write a Java program that asks the user to enter an array of integers in the main method. The program should prompt the user for the number of elements in the array and then the elements of the array. The program should then call a method named minGap that accepts the array entered by the user as a parameter and returns the minimum 'gap' between adjacent values in the array. The main method should then print the value returned by the method. The gap

Answer 1

In Java:

import java.util.*;

class Main {

public static void minGap(int intArray[], int arrlength) {

if(arrlength <2){return;}

int minm = Math.abs(intArray[1] - intArray[0]);

for (int i = 2; i < arrlength; i++)

minm = Math.min(minm, Math.abs(intArray[i] - intArray[i - 1]));

System.out.print("Minimum Gap = " + minm);

}

public static void main(String arg[]) {

Scanner input = new Scanner(System.in);

int arrlength;

System.out.print("Array Length: ");

arrlength = input.nextInt();

int[] intArray = new int[arrlength];

for(int i = 0;i<arrlength;i++){

intArray[i] = input.nextInt();

}

minGap(intArray, arrlength);

} }

Step-by-step explanation:

The minGap method begins here

public static void minGap(int intArray[], int arrlength) {

This checks if array length is 1 or 0. If yes, the program returns nothing

if(arrlength <2){return;}

If otherwise, this initializes the minimum gap to the difference between the 0 and 1 indexed array elements

int minm = Math.abs(intArray[1] - intArray[0]);

This iterates through the array elements

for (int i = 2; i < arrlength; i++)

This checks for the minimum gap

minm = Math.min(minm, Math.abs(intArray[i] - intArray[i - 1]));

At the end of the iteration, the minimum gap is printed

System.out.print("Minimum Gap = " + minm);

}

The main method begins here

public static void main(String arg[]) {

Scanner input = new Scanner(System.in);

This declares the length of the array

int arrlength;

This prompts the user for array length

System.out.print("Array Length: ");

This gets the user input

arrlength = input.nextInt();

This declares the array

int[] intArray = new int[arrlength];

The following iteration gets input for the array

for(int i = 0;i<arrlength;i++){

intArray[i] = input.nextInt();

}

This calls the minGap method

minGap(intArray, arrlength);

}