Question

An urn contains 6 red beads, 4 blue beads, and 2 green beads. If a single bead is picked at random, what is the probability that the bead is blue?

Give your answer as a fraction.

Answer 1

Step-by-step explanation: 6 + 4 + 2 = 12 (denominator)

Put 4 (blue beads) in numerator

4/12 reduces to 1/3

Final answer is 1/3

Answer 2

`|\Omega|=6+4+2=12\\|A|=4\\\\P(A)=(4)/(12)=(1)/(3)\approx33.3\%`