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Find an equation for the perpendicular bisector of the line segment whose endpoints are (7,−1) and (−9,3)

1 Answer

4 votes

Answer:

  • y = 4x + 5

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Find the slope of the line passing through the given points:

  • m = (3 - (-1)) / (-9 - 7)
  • m = 4/ (-16)
  • m = - 1/4

Perpendicular lines have negative- reciprocal slopes, so the perpendicular bisector has a slope of m = 4.

Find the midpoint of the segment with the endpoints (7, - 1) and (- 9,3).

  • x = (7 - 9)/2 = -2/2 = - 1
  • y = (-1 + 3)/2 = 2/2 = 1

Now, we need to find the line with a slope of 4 and passing through the point (- 1, 1). Use point-slope form and find the equation:

  • y - 1 = 4(x - (-1))
  • y - 1 = 4x + 4
  • y = 4x + 5
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User AMissico
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