Question

An oxide of lead 90.65% lead by weight.what is the empirical formula given that atomic mass of pb=207 and 0=16​

Answer 1

Pb3O4

Step-by-step explanation:

Element lead oxygen

Perc. 90.65%. (100-90.65)=9.35%

mol ratio. 90.65/207. 9.35/16

mol. 0.437923 0.584375

sim. rat.

0.437923/0.439723 0.584375/0.437923

ratio. 1 1.3

multiply the ratios by 3 (1×3). (1.3×3)

3 : 3.9

therefore the formula is Pb3O4.

I multiplied through by 3 so I can get a whole value/ a value easy to estimate.

I hope this helps.