Question

a 0.028 m cubed tank contains 0.082 kg of Nitrogen gas (N2) at a pressure of 2.89 atm. Find the temperature of the gas in degrees Celcius. Take the atomic weight of nitrogen to be N2 = 28 g/mol

Answer 1

Answer: 63.6 degrees Celsius

Step-by-step explanation:

Use the ideal gas law: PV = nRT (P is pressure, V is volume, n is number of moles, R is universal gas constant, T is temperature)

Rearrange the equation to isolate T: T = PV/nR

0.082 kg = 82 g

82/28 = 2.929 mol

Convert atm to Pa (pascals): 2.89*101325 = 292829.25 Pa

Now R can be used because we have the appropriate units.

T = PV/nR = (292829.25*0.028)/(2.929*8.314) = 336.749 K (Kelvin)

Convert K to Celsius: 336.749 - 273.15 = 63.6 degrees Celsius