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What force is necessary to stretch a spring 48 cm, if the spring constant is 270 n/m?

1 Answer

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Answer:

F= 129.6 N ≈ 130 N

Step-by-step explanation:

According to Hook's Law:

F = kx

F = Force necessary to stretch the spring

k = spring constant

x = displacement of the spring (stretch in the spring), in meters

Given x = 48 cm = 0.48 m

k = 270 N/m

F = kx

F = (270 N/m)(0.48 m) = 129.6 N

F = 129.6 N ≈ 130 N

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User Thea
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