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What is the pH of an aqueous solution at 25.0 °C that contains 3.98 × 10-9 M hydronium ion? A) 8.400 B) 5.600 C) 9.000 D) 3.980 E) 7.000

What is the pH of an aqueous solution at 25.0 °C that contains 3.98 × 10-9 M hydronium ion? A) 8.400 B) 5.600 C) 9.000 D) 3.980 E) 7.000
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What is the pH of an aqueous solution at 25.0 °C that contains 3.98 × 10-9 M hydronium ion? A) 8.400 B) 5.600 C) 9.000 D) 3.980 E) 7.000

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User Thomas Larsson
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1 Answer

4 votes
pH = -log[H+]
So, pH = -log(3.98x10^-9) = 8.40 A
answered
User Manish M Demblani
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