Question

Separate this redox reaction into its component half-reactions.
O2 + 2Cu --> 2CuO

Answer 1

O2 + 4e- --> O2 4-

Cu --> 2e- + Cu2+

Step-by-step explanation:

Oxygen is reduced and copper is oxidized.

We can thus write the half reactions:

O2 + 4e- --> O2 4-

Cu --> 2e- + Cu2+