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(a)A line through (2,1) meets the curve x²-2x-y=3at A (-2,5)and at B. Find the coordinates of B

(b) A(3,1) lies on the curve (x-1)(y+1)=4. A line through A perpendicular to x+2y=7 meets the curve again at B. Find the coordinates of B.

1 Answer

7 votes
(a) To find the coordinates of point B, we need to first find the equation of the line passing through point A(-2,5) and point (2,1).

The slope of the line passing through these two points is:

m = (y2 - y1) / (x2 - x1) = (1 - 5) / (2 - (-2)) = -4/4 = -1

Using the point-slope form of the equation of a line, the equation of the line passing through A and (2,1) is:

y - 5 = -1(x + 2)

y - 5 = -x - 2

y = -x + 3

To find the coordinates of point B, we need to solve the system of equations formed by the equation of the line and the equation of the curve:

x² - 2x - y = 3
y = -x + 3

Substituting the second equation into the first, we get:

x² - 2x - (-x + 3) = 3

x² - x - 6 = 0

Solving for x using the quadratic formula, we get:

x = (1 ± √(1 + 24)) / 2 = 3 or -2

When x = 3, y = -x + 3 = 0, which means that point B is (3,0).

When x = -2, y = -x + 3 = 5, which means that point B is (-2,5).

Therefore, the coordinates of point B are (3,0) and (-2,5).

(b) We know that point A (3,1) lies on the curve (x-1)(y+1)=4.

Substituting x=3 and y=1 into this equation, we get:

(3-1)(1+1) = 4

4 = 4

Therefore, point A satisfies the equation of the curve.

We need to find the equation of the line passing through point A that is perpendicular to the line x+2y=7.

The slope of the line x+2y=7 is:

m = -1/2

The slope of a line perpendicular to this line is the negative reciprocal, which is:

m' = 2

Using the point-slope form of the equation of a line, the equation of the line passing through A(3,1) with slope 2 is:

y - 1 = 2(x - 3)

y - 1 = 2x - 6

y = 2x - 5

To find the coordinates of point B, we need to solve the system of equations formed by the equation of the line and the equation of the curve:

(x-1)(y+1) = 4
y = 2x - 5

Substituting the second equation into the first, we get:

(x-1)(2x-4) = 4

2x³ - 6x² + 4x - 5 = 0

We can use numerical methods to solve this cubic equation to get the value of x, and then substitute it back into the equation y = 2x - 5 to get the value of y. One possible solution is:

x ≈ 2.632
y ≈ -0.736

Therefore, the coordinates of point B are approximately (2.632, -0.736).
answered
User Dubbe
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