Question

X + 2y =5, -x + 3y =6. which integers is the x value between?

Answer 1

• x is between 0 and 1

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Solve the system for x.

Use elimination method, multiply the first equation by 3 and the second equation by - 2, then add up to eliminate y:

• 3x + 6y + 2x - 6y = 15 - 12
• 5x = 3
• x = 3/5 = 06

The x value is between 0 and 1.