Question

if a substance x has a solubility of 7.0×10−13g ml−1, and a molar mass of 187 g mol−1, what is the molar solubility of the substance?

Answer 1

The molar solubility of substance X is calculated by dividing the given solubility in grams per milliliter by the molar mass in grams per mole and converting to moles per liter, resulting in 3.74 × 10-12 mol L-1.

Step-by-step explanation:

To find the molar solubility of substance X, we must first convert the solubility in grams per milliliter to moles per liter (mol L-1). The solubility is given as 7.0 × 10-13 g mL-1, and the molar mass is 187 g mol-1. By dividing the solubility by the molar mass, we can find the molar solubility:

Solubility (mol L-1) = Solubility (g mL-1) / Molar mass (g mol-1)

Molar Solubility = (7.0 × 10-13 g mL-1) / (187 g mol-1)

To find the solubility in mol L-1, we multiply the solubility in g mL-1 by 1000 mL per L to convert to g L-1 and then divide by the molar mass:

Molar Solubility = (7.0 × 10-13 g mL-1 × 1000 mL L-1 / 187 g mol-1)

Molar Solubility = (7.0 × 10-10 g L-1 / 187 g mol-1)

Molar Solubility = 3.74 × 10-12 mol L-1

Answer 2

3.7E-12 M

Step-by-step explanation:

(7.0E-13 g/mL)(1000 mL / 1 L) = 7.0E-10 g/L

(7.0E-10 g/L)(mol / 187 g) = 3.7E-12 mol/L = 3.7E-12 M