Question

based on the following equation, if we want to produce 25 g nacl, how many grams of mgcl2 would we need? mgcl2 2naoh→mgoh2 2nacl

Answer 1

To produce 25 g of NaCl, you would need 20.5 g of MgCl2.

Step-by-step explanation:

To determine the number of grams of MgCl2 needed to produce 25 g of NaCl, we need to use the balanced chemical equation:

MgCl2 + 2NaOH → Mg(OH)2 + 2NaCl

From the equation, we can see that 2 moles of NaCl are produced for every mole of MgCl2. The molar mass of MgCl2 is 95.21 g/mol. We can use this information to calculate the grams of MgCl2 needed:

(25 g NaCl) x (1 mol NaCl/58.44 g NaCl) x (1 mol MgCl2/2 mol NaCl) x (95.21 g MgCl2/1 mol MgCl2) = 20.5 g MgCl2

Answer 2

To produce 25 g NaCl, you would need 20.49 g MgCl2.

Step-by-step explanation:

To determine the amount of MgCl2 needed to produce 25 g NaCl, we need to use the balanced chemical equation:

MgCl2 + 2NaOH → Mg(OH)2 + 2NaCl

From the equation, we can see that the ratio between MgCl2 and NaCl is 1:2. This means that for every 1 mole of MgCl2, we will produce 2 moles of NaCl.

To calculate the grams of MgCl2 needed, we can use the molar mass of NaCl to convert it to moles, then use the mole ratio to convert to moles of MgCl2, and finally convert back to grams of MgCl2.

Let's calculate:

25 g NaCl * (1 mole NaCl / 58.44 g NaCl) * (1 mole MgCl2 / 2 moles NaCl) * (95.21 g MgCl2 / 1 mole MgCl2) = 20.49 g MgCl2