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In the super market there are five shopkeepers A, B, C, D, E. If shopkeeper A sells his 2/3 of products in a day, B sells 3/7 of products, C sells 4/5 of products in a day, D sells 5/6 of products in a day and E sells 7/8 of products in a day, who sells more products in a day? Represent each fraction and find the largest fraction and the smallest fraction.

asked
User Svaor
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1 Answer

4 votes


To compare the amount of products sold by each shopkeeper, we need to find the common denominator of all fractions. The smallest common multiple of the denominators 2, 3, 5, 6, and 8 is 120, so we will use that as the common denominator.

- Shopkeeper A sells 2/3 of products, which is equivalent to 80/120.
- Shopkeeper B sells 3/7 of products, which is equivalent to 51.428.../120.
- Shopkeeper C sells 4/5 of products, which is equivalent to 96/120.
- Shopkeeper D sells 5/6 of products, which is equivalent to 100/120.
- Shopkeeper E sells 7/8 of products, which is equivalent to 105/120.

To compare the fractions, we can convert them all to decimals or find a common numerator. To find the largest fraction, we can look for the highest numerator. To find the smallest fraction, we can look for the lowest numerator.

- Shopkeeper A sells 80/120 = 0.666...
- Shopkeeper B sells 51.428.../120 = 0.4285...
- Shopkeeper C sells 96/120 = 0.8
- Shopkeeper D sells 100/120 = 0.8333...
- Shopkeeper E sells 105/120 = 0.875

So, shopkeeper E sells the most products in a day, while shopkeeper B sells the least.

The largest fraction is 7/8, which represents the fraction of products sold by shopkeeper E.

The smallest fraction is 3/7, which represents the fraction of products sold by shopkeeper B.
answered
User Bluppfisk
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7.5k points
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