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\int\limits^(i/2)_i {e^(z/2)} \, dx

\int\limits^(i/2)_i {e^(z/2)} \, dx
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\int\limits^(i/2)_i {e^(z/2)} \, dx

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User Bollo
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1 Answer

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The integral of e^z/2 is xe^z/2
Ans: (i/2)xe^z/2 - ixe^z/2= -(i/2)xe^z/2
\int\limits^(i/2)_i {e^(z/2)} \, dx-example-1
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User Tej Kiran
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