Question

Given that the initial rate constant is 0.0120s−1 at an initial temperature of 29 ∘C , what would the rate constant be at a temperature of 160 ∘C for the same reaction described in Part A?

Answer 1

To calculate the rate constant at a different temperature for the same reaction, we can use the Arrhenius equation:

k2 = A*e^(-Ea/R*(1/T2 - 1/T1))

where k2 is the rate constant at the new temperature, A is the frequency factor (which is assumed to be constant), Ea is the activation energy for the reaction, R is the gas constant (8.314 J/mol*K), T2 is the new temperature in Kelvin, and T1 is the initial temperature in Kelvin.

To solve this equation, we need to know the activation energy and frequency factor for the reaction. Do you have this information available?