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A map of the world has a perimeter of 26 feet. Its area is 40 square feet. What are the dimensions of the map?

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User Mfazekas
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2 Answers

5 votes

Answer:

To solve this problem, we can use the formulas for the perimeter and area of a rectangle:

Perimeter = 2 * (length + width) Area = length * width

Since we're dealing with a square in this case, we can simplify these formulas slightly:

Perimeter = 4 * side Area = side^2

where "side" is the length of one side of the square.

Given the perimeter and area of the map, we can set up two equations in terms of "side":

4 * side = 26 (since the perimeter is 26 feet) side^2 = 40 (since the area is 40 square feet)

From the first equation, we can solve for "side" by dividing both sides by 4:

side = 6.5

Substituting this value into the second equation, we get:

(6.5)^2 = 40.25

Since the area of the map is supposed to be 40 square feet, this means that the map's dimensions are not actually a square, but instead a rectangle with dimensions that are very close to 6.5 feet by 6.17 feet (since 6.5 * 6.17 = 40.05 square feet, which is very close to 40).

Therefore, to answer the question "What are the dimensions of the map?", we can say that the map's dimensions are approximately 6.5 feet by 6.17 feet.

Explanation:

answered
User Sakura
by
8.1k points
3 votes

Answer: 80 + 2L*L = 26*L

Explanation:

answered
User John Kraft
by
8.0k points

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