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1) If I have 8 moles of a gas at a pressure of 15.6 atm and a volume of 42 liters, what

is the temperature?

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User Glezo
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To solve this problem, we can use the ideal gas law, which relates the pressure, volume, temperature, and number of moles of a gas. The ideal gas law is given by:

PV = nRT

where:
P = pressure (in atm)
V = volume (in liters)
n = number of moles
R = gas constant (0.0821 L·atm/mol·K)
T = temperature (in Kelvin)

We can rearrange this equation to solve for the temperature:

T = PV / (nR)

Plugging in the given values, we get:

T = (15.6 atm) x (42 L) / (8 mol x 0.0821 L·atm/mol·K)

Simplifying this expression, we get:

T = 758.16 K

Therefore, the temperature of the gas is 758.16 K.
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User Khemraj Sharma
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