asked 127k views
5 votes
Factor completely 625x4 - 81.

O (5x - 3)(5x - 3)(25x² + 9)
O (5x - 3)(5x+3)(25x² - 9)
O (5x+3)(5x + 3)(25x² + 9)
O (5x - 3)(5x+3)(25x² + 9)

asked
User Lazaros
by
7.8k points

1 Answer

2 votes

Answer:

A

Explanation:

We can factor 625x^4 - 81 by recognizing it as the difference of two squares:

625x^4 - 81 = (25x^2)^2 - 9^2

This can be further simplified using the formula for the difference of squares, which states that:

a^2 - b^2 = (a + b)(a - b)

In this case, a = 25x^2 and b = 9, so we have:

(25x^2 + 9)(25x^2 - 9)

We can then use the difference of squares formula again to factor 25x^2 - 9:

25x^2 - 9 = (5x)^2 - 3^2 = (5x + 3)(5x - 3)

Substituting this into our original expression, we get:

625x^4 - 81 = (25x^2 + 9)(25x^2 - 9) = (25x^2 + 9)(5x + 3)(5x - 3)

Therefore, the fully factored form of 625x^4 - 81 is (25x^2 + 9)(5x + 3)(5x - 3). Answer: (A) (5x - 3)(5x - 3)(25x² + 9)

answered
User Caneta
by
8.6k points

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