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5 votes
Please help help help with number 6!

Please help help help with number 6!-example-1
asked
User Souldzin
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8.6k points

1 Answer

6 votes

Answer:

Q6. x = 8.1 ***

Q7 x = 27.87

***For question 6: Your picture of question 6 is so blurred I could not really make out the angle; I took it as 36° . If it is something else, use the formula given below with the correct angle and compute **

Explanation:

In right triangle, with one of the angles = θ , the following relationships hold


\cos \theta = (adjacent)/(hypotenuse)\\\\\sin\theta = (opposite)/(hypotenuse)\\\\\tan\theta = (opposite)/(adjacent)\\

where

adjacent means side adjacent to θ
opposite means side opposite to θ

In the given figure in Q6,

θ = 36° (I had difficulty making out the picture)

adjacent = x

hypotenuse = 10

so


\cos 36^\circ = (x)/(10)\\\\x = 10 \cdot \cos 36^\circ\\\\x = 10 \cdot 0.809\\\\x = 809\\\\\text{x = 8.1 rounded to the nearest tenth}

I have answered question 7 also since it is very similar:


\sin 35^\circ = (16)/(x)\\\\x = (16)/(\sin 35^\circ)\\\\\\= (16)/(0.574)\\\\\\= 27.8745\\\\= 27.87 \text{ to the nearest hundredth\\}

answered
User YYY
by
8.5k points

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