Question

What is the equation of the line perpendicular to x-2y=8 and passes through the point (4,-3)

Answer 1

• x-2y=8

Bring to slope intercept form

• 2y=x-8
• y=x/2-4

As per y=MX+c form

m is slope

• so here slope is 1/2

Now perpendicular lines have slope negative reciprocal to each other

so slope of perpendicular line

• -2

Now equation of line

• y-y1=m(x-x1)
• y+3=-2(x-4)
• y+3=-2x+8
• y=-2x+5