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Perform the indicated operations. Assume that no denominator has a value of 0.

10-5g/6+3g÷5/12+6g

1 Answer

2 votes

To perform the indicated operations with the given expression, we need to follow the order of operations.

First, we need to simplify 6+3g in the denominator of the first fraction.

Then, we need to divide 10-5g by the result from the first step.

Finally, we need to multiply by the result of the fraction in the numerator.

So the solution is:

(10-5g)/((6+3g)/(5/12+6g))

We can simplify the denominator further by finding a common denominator for 5/12 and 6g. A common denominator is 12, so we multiply 5/12 by 1 = 12/12 and 6g by 2 = 24/12. Then we get:

(10-5g)/((6+3g)/(12/12+24g/12))

(10-5g)/((6+3g)/(36g+12)/12))

(10-5g)/(6+3g)*(12)/(36g+12)

(10-5g)/3(2+g)*12/12(3g+1)

(10-5g)/3(2+g)*(3g+1)

So the final solution is:

(10-5g)(3g+1)/(3(2+g))

or

(5g-10)(3g+1)/(3(g+2))

answered
User Ghchoi
by
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