Question

I need this done Im stressing you can do one if u want

Answer 1

`\cfrac{a-3}{10}+\cfrac{a-5}{5}=\cfrac{1}{2}\implies \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{10}}{10\left( \cfrac{a-3}{10}+\cfrac{a-5}{5} \right)=10\left( \cfrac{1}{2} \right)} \\\\\\ (a-3)+2(a-5)=5\implies a-3+2a-10=5\implies 3a-13=5 \\\\\\ 3a=18\implies a=\cfrac{18}{3}\implies a=6 \\\\[-0.35em] ~\dotfill`

`\cfrac{2}{n-3}+\cfrac{2}{n+5}=\cfrac{5n-7}{n^2+2n-15}\implies \cfrac{2}{n-3}+\cfrac{2}{n+5}=\cfrac{5n-7}{(n-3)(n+5)} \\\\\\ \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{(n-3)(n+5)}}{(n-3)(n+5)\left( \cfrac{2}{n-3}+\cfrac{2}{n+5} \right)=(n-3)(n+5)\left( \cfrac{5n-7}{(n-3)(n+5)} \right)} \\\\\\ (n+5)2~~ + ~~(n-3)2=5n-7\implies 2n+10+2n-6=5n-7 \\\\\\ 4n+4=5n-7\implies 4=n-7\implies 11=n`