Question

Please help me it is diffiult

Answer 1

Sin(C) =
`(3)/(5)`.

Cos(B) =
`(3)/(5)`

Sin(C) and Cos(B) =
`(3)/(5)`

Explanation:

To solve this we need to remember the trigonometry ratios. Sin is the side opposite the angle over the hypotenuse. Cos is the side touching the angle divided by the hypotenuse and Tan is the side opposite the angle divided by the side touching the angle.

Knowing this can help us solve our problem.

Let us first solve for sin C. To solve for this let us look for the side opposite (or directly across) of angle c. This side is side AB or 39. The next thing we need to look for is the hypotenuse. The hypotenuse is the side directly across the right angle. This side is side CB or 65.

Dividing these gives us our first fraction
`(39)/(65)`. Now we need to simplify this. 39/65 implied is
`(3)/(5)`. This is sin of C.

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To solve for cos of B we have to look for the side directly next to the angle. This is side AB or 39. The next step is to identify the hypotenuse. The hypotenuse is 65, so Cos of b is
`(39)/(65)` or
`(3)/(5)`.