To solve this problem, we'll need to use the formula for the sum of an arithmetic series:
S_n = n/2(2a + (n-1)d)
where S_n is the sum of the first n terms of the series, a is the first term, and d is the common difference between terms.
We're given that a = 2 and n = 8, and we know that the sum of the first 8 terms is 1472. So we can plug in these values and solve for d:
1472 = 8/2(2(2) + (8-1)d)
1472 = 4(4 + 7d)
1472 = 16 + 28d
1456 = 28d
d = 52
Now that we know the common difference is 52, we can use the formula for the nth term of an arithmetic series to find the 8th term:
a_8 = a + (n-1)d
a_8 = 2 + (8-1)52
a_8 = 2 + 364
a_8 = 366
So the 8th term in the series is D) 366.