Question

Find the distance between (-9, 8) and (-1,8).
The distance is how many units?

Answer 1

• 8 units

Explanation:

Here,

We know that,

`\large \bf \: Distance= \sqrt{(x_2 - x_ 1) {}^(2) + (y_ 2 -y_1) {}^(2) }`

• x1= -9
• x2 = -1
• y1 = 8
• y2 = 8

So ,

Putting the value of x and y in the given formula

We get,

`\large\sf{ \: = \sqrt{ \{ \: - 1 - ( - 9) \} {}^(2) + (8 - 8) {}^(2) } \: }`

`\large\sf{ = \sqrt{(8) {}^(2) + (0) {}^(2) } }`

`\large\sf{ \: = √(64 + 0) }`

`\large\sf{ = √(64) }`

`\large\bf \blue { = 8 \: unit}`

Thus,

• distance between (-9, 8) and (-1,8) is in 8 units.

`{\underline {\underline{ \rule{200pt}{8pt}}}}`