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If p(x)=0.5(x-5)^2+14, what is the value of p(3)

If p(x)=0.5(x-5)^2+14, what is the value of p(3)
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If p(x)=0.5(x-5)^2+14, what is the value of p(3)

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User Anuj Pradhan
by
8.2k points

1 Answer

5 votes

Answer:

p(3) = 16

Explanation:

to evaluate p(3) substitute x = 3 into p(x)

p(3) = 0.5(3 - 5)² + 14

= 0.5(- 2)² + 14

= 0.5(4) + 14

= 2 + 14

= 16

answered
User MLKing
by
8.0k points
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