Question

If sin^ - 1 beta = pi/2 - cos¹a, what is the value of ẞ?​

Answer 1

We know that
`sin^-1(beta) + cos^-1(a) = pi/2` (using the identity
`sin^-1(x) + cos^-1(x) = pi/2`)

So,
`sin^-^1(beta) = pi/2 - cos^-^1(a)`

Substituting the given value, we get:

`pi/2 - cos^-^1(a) = pi/2 - cos^-^1(a)`

This is true for any value of a and β. Therefore, we cannot determine the value of β from the given equation.