Question

Unpolarized light with an original intensity i0i0 passes through two ideal polarizers having their polarizing axes turned at 120 ∘∘ to each other. After passing through both polarizers, the intensity of the light is _____I0

Answer 1

A = cos 120 = cos 60 = .5 amplitude of transmission

The sign is not important regarding the angle of transmissio

I2 = .5^2 I1 = I1 / 4 Intensity proportional to amplitude squared

Io / 4 is correct