Question

The lenght is (x+5) and the width is (x+3). Find the Area if the

Perimeter is 24.


40
O 20
O 50
O 35

Answer 1

If the length of a rectangle is x + 5, and the width is x + 3, then its perimeter can be expressed as:

Perimeter = 2(length + width)

P = 2(x + 5 + x + 3)

P = 4x + 16

We are given that the perimeter is 24, so we can set up an equation:

4x + 16 = 24

Solving for x:

4x = 8

x = 2

Now that we know x = 2, we can find the length and width of the rectangle:

Length = x + 5 = 2 + 5 = 7

Width = x + 3 = 2 + 3 = 5

The area of a rectangle is given by:

Area = Length x Width

So the area of this rectangle is:

Area = 7 x 5 = 35

Therefore, the area of the rectangle is 35 square units.

Explanation:

The correct answer is:

Area = Length x Width

Area = (x + 5) x (x + 3)

We know that the perimeter is 24:

Perimeter = 2(Length + Width)

24 = 2[(x + 5) + (x + 3)]

24 = 2(2x + 8)

24 = 4x + 16

8 = 4x

x = 2

So the length and width are:

Length = x + 5 = 7

Width = x + 3 = 5

Therefore, the area of the rectangle is:

Area = Length x Width

Area = 7 x 5

Area = 35

Therefore, the answer is O 35.

Answer 2

area=35

Explanation:

x+5+x+3+x+5+x+3=24

4x+16=24

4x=8

x=2

(2+5)(2+3)

4+6+10+15

area=35