Question

Last month the electric meter reading was 6452 kwh this month the reading was 8328 kwh. if electricity costs 3.40 per kwh. how much will one pay.

a.the problem asked?

b. the given facts are?

c. the hidden question is?

d. the operation to be used are?

e. the number sentence is?

f. the solution is?

g. the answer is?

Answer 1

Therefore, the electricity bill for this month is 6378.40.

Explanation:

a. The problem asked is to calculate the electricity bill for this month.

b. The given facts are:

* Last month's electric meter reading: 6452 kWh

* This month's electric meter reading: 8328 kWh

* Electricity cost per kWh: 3.40

c. The hidden question is: How much electricity was used this month?

d. The operations to be used are:

* Subtraction to find the difference in the electric meter readings

* Multiplication to find the total cost of electricity used this month

e. The number sentence is:

(8328 kWh - 6452 kWh) * 3.40 = ?

f. The solution is:

1876 * 3.40 = 6378.40

g. The answer is: 6378.40

Therefore, the electricity bill for this month is 6378.40.