Question

Is Y=2x^2+3x-2 real roots ?

Answer 1

Yes

Explanation:

x = (-b ± sqrt(b^2-4ac)) / 2a

In this case, a=2, b=3, and c=-2. Substituting these values into the quadratic formula, you get:

x = (-3 ± sqrt(3^2 - 4(2)(-2))) / 2(2)

x = (-3 ± sqrt(25)) / 4

x = (-3 ± 5) / 4

So the roots are:

x = (-3 + 5) / 4 = 1/2

x = (-3 - 5) / 4 = -2