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A child bounces a 48 g superball on the side- walk. The velocity change of the superball is from 22 m/s downward to 17 m/s upward. 1 If the contact time with the sidewalk is 800…

A child bounces a 48 g superball on the side- walk. The velocity change of the superball is from 22 m/s downward to 17 m/s upward. 1 If the contact time with the sidewalk is 800…
asked 71.5k views
3 votes
A child bounces a 48 g superball on the side-

walk. The velocity change of the superball is

from 22 m/s downward to 17 m/s upward.

1

If the contact time with the sidewalk is

800

s, what is the magnitude of the average force

exerted on the superball by the sidewalk?

asked
User Saket Mittal
by
8.5k points

1 Answer

3 votes

Answer:

0,3

Step-by-step explanation:

force = mass ×accelaration

answered
User Simon Ninon
by
7.9k points
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