Question

The perimeter of a rectangular painting in an art museum measures 108 inches. The length of the painting is 3 inches less than

twice the width. Which system of equations can be used to determine I, the length of the painting, and w, the width?

A

21+2w=108

1=2w+3

B

21+2w=108

I=2w-3

C

7+w= 108

1=2w-3

D

+w=108

1=2w+3

Answer 1

B. 2l+2w=108; l =2w-3

Explanation:

You want the system of equations that expresses the relationships ...

• the painting perimeter is 108 inches
• the length is 3 inches less than twice the width

Equations

Letting l and w represent length and width, respectively, the relations are ...

108 = 2l +2w . . . . . the perimeter is 108 inches

l = 2w -3 . . . . . . . . the length is 3 less than twice the width

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Additional comment

The first equation makes use of the perimeter equation for a rectangle:

P = 2l +2w