Answer:
a. Step 1) From the sample, the sample percentage of cell phone users who develop the cancer is 0.0317%.
Step 2) The sample size is 420,064. Since the sample is large, we can assume the sampling distribution of sample percentages is approximately normal.
Step 3) The critical Z-value for a 90% CI is Z=1.645.
Step 4) Compute the margin of error:
MoE = Z * sqrt(p(1-p)/n) = 1.645 * sqrt(0.0317*(1-0.0317)/420,064) = 0.000330
Step 5) The 90% CI is: (0.0317 - 0.000330, 0.0317 + 0.000330) = (0.0284, 0.0350)
b. The answer is OC: No, because 0.0315% is included in the confidence interval.
Since 0.0315% falls within the confidence interval, we do not have enough evidence to conclude that the cancer rate for cell phone users is different than for non-users. The interval is reasonably wide due to the small absolute difference in percentages, so more data may be needed to detect a difference, if there is one.