Answer: Without knowing the specific spinner in question, it's impossible to give an exact answer. However, I can give some general guidance on how to approach this type of probability question.
First, you need to determine how many possible outcomes there are when spinning the spinner. Let's say, for example, that the spinner has six equally sized sections, each labeled with a different number: 1, 2, 3, 4, 5, and 6.
Next, you need to determine how many of those outcomes are prime numbers. In this case, there are four prime numbers: 2, 3, 5, and 7 (if we assume the spinner goes up to 7). Therefore, there are four possible outcomes that are prime numbers.
To find the probability of spinning two prime numbers in a row, you need to determine the probability of spinning a prime number on the first spin, and then multiply that by the probability of spinning a prime number on the second spin, given that a prime number was spun on the first spin.
So, the probability of spinning a prime number on the first spin is 4/6 or 2/3 (assuming a six-section spinner), since there are four prime numbers out of six possible outcomes.
Now, if a prime number was spun on the first spin, there are only five possible outcomes left for the second spin, since the outcome of the first spin is already determined. And out of those five outcomes, only three are prime numbers. So the probability of spinning a prime number on the second spin, given that a prime number was spun on the first spin, is 3/5.
To find the overall probability of spinning two prime numbers in a row, we multiply the probabilities of the two spins:
P(2 prime numbers) = (2/3) x (3/5) = 6/15 = 2/5
So the probability of spinning two prime numbers in a row is 2/5, or 40% (assuming a six-section spinner with four prime numbers).