asked 124k views
3 votes
The turret of the castle was covered in silver. What is the square area of silver used to cover the structure is the diameter is approximately 10 feet and the height is 12 feet?

Round to the nearest tenth.

asked
User Arseny
by
8.4k points

2 Answers

2 votes

Final answer:

To find the square area of silver used to cover the cylindrical turret with a 10 foot diameter and 12 foot height, calculate the curved surface area using the formula 2πrh. The calculated surface area is 376.8 square feet when rounded to the nearest tenth.

Step-by-step explanation:

The student's question pertains to the calculation of the surface area of the silver that covers a turret, which is a cylindrical structure. First, the surface area of a cylinder is calculated using the formula 2πrh + 2πr², where 'r' is the radius of the cylinder's base and 'h' is its height. Given the diameter of the turret is 10 feet, the radius is 5 feet. So, the curved surface area (ignoring the top and bottom) would be 2π(5 feet)(12 feet). To calculate, multiply 2 by π (approximately 3.1416) by the radius (5 feet) by the height (12 feet).

Surface Area = 2πrh = 2π(5)(12) = 2π(60) = 120π = 376.8 square feet (rounded to one decimal place).

The student is advised to use the correct formula and units for calculating surface areas. Furthermore, if the turret's top and bottom were also covered in silver, those areas would need to be included to calculate the total surface area covered by silver. However, in this case, we are only considering the lateral surface area.

answered
User Murakami
by
8.2k points
4 votes

Answer:

282.74

Step-by-step explanation:

π·5·(5+122+52)≈282.74334

answered
User Ceoehis
by
9.0k points
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