asked 45.8k views
4 votes
If the area of a rectangle is 12n^12 -30n^6+168n^3 and the length is 6n^3. What is the width

asked
User TinusSky
by
7.6k points

1 Answer

0 votes

Answer:

width = 2n^9 - 5n^3 + 28

Explanation:

Area = length X width

width = area / length

= (12n^12 - 30n^6 + 168n^3) / (6n^3)

= (12n^12 / (6n^3) ) - (30n^6 / (6n^3)) + (168n^3 / (6n^3))

= (12/6)n^(12 - 3) - (30/6)n^(6 - 3) + (168/6)n^(3 -3)

= 2n^9 - 5n^3 + 28n^0

= 2n^9 - 5n^3 + 28

answered
User JorgeDeCorte
by
7.0k points
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