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2. What are the zeroes of the function? (1 point)

y=(x-2)(x-3)(x+3)
O-2, 3,-3
02, 3,-3
02,-3,-3
O-2, 3, 3

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User Majkrzak
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1 Answer

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The zeroes of the function I think would be 0,-2
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User Relevart
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