The nth term of an arithmetic sequence can be represented by the formula:
a(n) = a(1) + (n-1)d
where a(1) is the first term of the sequence, d is the common difference, and n is the number of terms.
In this case, we are given that a(11) = 57 and d = 6. We can use this information to find a(1) by rearranging the formula:
a(1) = a(11) - (11-1)d
a(1) = 57 - 10(6)
a(1) = 57 - 60
a(1) = -3
Therefore, the rule for the nth term of this arithmetic sequence is:
a(n) = -3 + (n-1)6
or equivalently,
a(n) = 6n - 9.
Have a Great Day
~~~Harsha~~~